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**Memory Based Question Asked in SBI PO Prelims 2018 Download Pdf**

**Memory Based Question Asked in SBI PO Prelims 2018 Download Pdf**

*Hello Aspirants, as we know that today was second day of sbi PO prelims exam. So we are providing Memory Based questions asked in SBI PO exam pattern held on 8th July 2018. Here we will are providing you the section-wise Memory Based Questions. We are updating one by one all the questions stay tuned and book mark this page.*

**SBI PO Questions Asked on 8th July 2018 1st 2nd 3rd 4th Shift Prelims Exam**

**SBI PO Questions Asked on 8th July 2018 1st 2nd 3rd 4th Shift Prelims Exam**

**#1 SBI PO English Questions Asked on 8th July Paper**

**#1 SBI PO English Questions Asked on 8th July Paper**

**#1 SBI PO English Questions Asked on 8th July Paper**

**English (1st Shift**)

*a) What is the synonym of ‘shape’?*

*b) The _________of primary education to _______ students future bright.*

*A. Purpose, Bring*

*B. Role, Make*

*C. Importance, Building*

**English (2nd Shift**)

*a) What is the antonyms of ‘Strength’?*

*b) What is the antonyms of ‘Neglect’?*

*c) What is the synonym of ‘Blips’?*

**#2 SBI PO Quant Question Asked in 8th July Paper**

**#2 SBI PO Quant Question Asked in 8th July Paper**

**Number Series**– Missing number series questions were asked. The questions were easy. Following number series questions were asked –

*1. 200, 101, 102, 154 ?*

*2. 5000, 1000, 400, 320, ?,*

*3. 163844, 9, 17, 35, ?,*

*4. 1392, 15, 59, 117, 116 ?*

*5. 26, 138, 29, 142, 34, 148 ?***Missing Number Series: (1st Shift)**

*a) 200, 101, 102, 154, ?*

*b) 5000, 1000, 400, 320, ?, 1638.4*

*Ans: 5000/5 = 1000*

*1000/2.5 = 400*

*400/1.25 = 320*

*320/0.625 = 512 (Answer)*

*512/0.3125 = 1638.4*

*c) 4, 9, 17, 35, ?, 139*

*d) 2, 15, 59, 117, 116, ?*

*Ans: x8-1, x4-1, x2-1, x1-1, x0.5-1….. hence answer wil be 57*

*e) 26, 138, 29, 142, 34, 148, ?***Missing Number Series: (2nd Shift)***a) 1392, 15, 59, 117, 116, ?***Number Series (3rd Shift) – Find the Wrong**

*a) 4, 12, 22, 55, 110, 326, 375*

*b) 2, 11, 53, 204, 624*

*c) 50, 39, 53, 35, 56, 32, 59*

*d) 400, 200, 210, 300, 600, 1500, 4500***Miscellaneous**

*a) 16√2 is a diagonal of square then find the area of circle?**b) A & B invest some amount for 2yr & 3yr with rate 10% CI & 12% SI respectively. total profit frm both is 19000 and interest from A is 1/8 of B total amount …find A’s total amount invested earlier?**c) X^2 = 144*

*Y^2 = √81*

*a) x > y*

*b) x < y*

*c) x >= y*

*d) x <= y**d) Two unbiased dices are tossed simultaneously. What is the probability that the sum of the two outcomes is a factor of 20?**e) Item A sold at 25% profit and B at 25% loss. CP of B is 20% more than A. Difference between the profit of A and loss of B is 13.05. Find CP of A?**f) Upstream+Downstream speed=45 Km/H Downstream:stream=8:1. Then find the distance covered in 6hr downstream.*

**#3 SBI PO Reasoning Question Asked in 8th July Paper**

**#3 SBI PO Reasoning Question Asked in 8th July Paper**

*a) There were 8 people named K, L, M, N, P, Q, R & S. Four months were given i.e February, April, June & August. P & Q were born on the same date. Q was born on the month of 31 days. R was in the centre with equal no. of people before & after him.**b) Is there any meaningful word can be formed from letter H, T, O, A?**c) b) Is there any meaningful word can be formed from letter S, O, A, T?**d) All were facing north. And statements given were M is fifth to the left of one having 12 number, only one person is between M and one having 9 number, person having number 9 is third from left end, there are 4 persons between T and M, there two persons between T and person having 9 Number, person having number 15 is fifth to the right of M, M is 13 th from one of the two ends and two conditions were given about position of X.**e) Machine Input (2nd Shift)*

*i) B 19 F 27 M 50 39 P Y 40*

**Previous Shifts Questions Below**

**Set (1-5) Read the following information and answers the given questions.**

**In a college, three programming languages are taught. Out of 1200 students, each one is required to study at least one of the three languages which are BASIC, COBAL and C. 40 students study all the three languages. 404 students study only C, 222 students study only BASIC, 500 students study COBAL, 114 students study both C and BASIC and 388 students study only COBAL.**

*1. How many students study two programming languages only such that at least one of the two languages is COBAL?*

*(A) 36*

*(B) 72*

*(C) 48*

*(D) 60*

*(E) 80*

*2. What is the number of students who study exactly two languages?*

*(A) 146*

*(B) 126*

*(C) 136*

*(D) 156*

*(E) 132*

*3. If the number of students study C language is 554, then what is the number of students study BASIC language?*

*(A) 348*

*(B) 372*

*(C) 336*

*(D) 308*

*(E) 318*

*4. If the number of students study BASIC language is 384, then what is the number of students study both COBOL and C languages?*

*(A) 24*

*(B) 36*

*(C) 72*

*(D) 48*

*(E) 64*

*5. What is the total number of students study C and BASIC languages?*

*(A) 720*

*(B) 772*

*(C) 812*

*(D) 782*

*(E) 834*

**Set (6 – 10) Read the following information and answers the given questions.**

**Dhoni and kohli study in the same school and go to school by walk. Dhoni starts from his house at 8.20 a.m. usually. On Tuesday he walked at 6 km/hr and was late by 8 minutes. On Wednesday he increased his speed to 8 km/hr and reached 8 minutes early. Kholi starts from his house at 8.10 a.m. usually. On Tuesday, he walked at 6.5 km/hr and was late by 12 minutes. On Wednesday he increased his speed to 8 km/hr and reached 6 minutes early.**

*6. What is the distance from Dhoni house to School?*

*(A) 6.4 km*

*(B) 7.2 km*

*(C) 5.6 km*

*(D) 7.6 km*

*(E) None of these*

*7. If both Dhoni and Kohli reached the school at the right time on Thursday, what were their walking speeds respectively?*

*(A) 48/7 km/hr, 52/7 km/hr*

*(B) 49/8 km/hr, 27/4 km/hr*

*(C) 57/7 km/hr, 31/5 km/hr*

*(D) 61/9 km/hr, 33/7*

*(E) None of these*

*8. What is the distance from kohli house to school?*

*(A) 8 km*

*(B) 9.6 km*

*(C) 9.8 km*

*(D) 10.4 km*

*(E) 10.2 km*

**SET (9-11) Read the following information and answers the questions.**

**There are four mixtures of water and milk.**

**Mixture A contains water and milk in the ratio 5: 4**

**Mixture B contains water and milk in the ratio 1: 5**

**Mixture C contains water and milk in the ratio 4:5**

**Mixture B and C mixed in 1: 3 result in mixture D.**

*9. What is the ratio of water and milk in mixture D?*

*(A) 3:5*

*(B) 3:4*

*(C) 4: 3*

*(D) 5: 3*

*(E) 2: 3*

*10. In what ratio should mixture A and B be mixed in order to get mixture C?*

*(A) 2:3*

*(B) 3: 4*

*(C) 1:5*

*(D) 5: 2*

*(E) 2: 5*

*11. In what ratio should mixtures A and D be mixed so that the volumes of water and milk are equal in the resultant mixture?*

*(A) 4: 7*

*(B) 7: 4*

*(C) 9: 4*

*(D) 6:1*

*(E) 1:2*

**Set (12 – 16) Study the following passage and answers the questions.**

**A certain number of students are interested in different activities like Singing, painting and dancing. 240 of them are interested in only painting. The total number of students who are interested in both painting and singing is 6/5 of the number of students who are interested in only painting. 5/8 of the number of students interested in both painting and singing are interested in all the three activities. The number of students interested in both singing and dancing but not painting is the average of the number of students who are interested in only painting and the number of students who are interested in all the three activities. The number of students who are interested in only dancing is 30% more than the number of students who are interested in both singing and dancing but not painting. The number of students interested in singing is same as the number of students interested in dancing. The number of students interested in only singing is half the number of students interested in more than one activity.**

*12. How many students like any of the given activities?*

*(A) 1472*

*(B) 1498*

*(C) 1512*

*(D) 1523*

*(E) 1533*

*13. What percentage of the total number of students likes all the three activities?*

*(A) 12.23%*

*(B) 11.90%*

*(C) 13.33%*

*(D) 16.67%*

*(E) 14.28%*

*14. What is the difference between the number of people who like dancing but not painting and the number of people who like painting but not dancing?*

*(A) 145*

*(B) 125*

*(C) 175*

*(D) 135*

*(E) 150*

*15. How many students like exactly two activities?*

*(A) 477*

*(B) 457*

*(C) 468*

*(D) 448*

*(E) 486*

*16. How many students like only Dancing?*

*(A) 273*

*(B) 265*

*(C) 257*

*(D) 270*

*(E) 250*

**SET (17 – 20) Study the following paragraph and answer the questions.**

**In Chennai Anna University, the first year is a foundation program for all the students after which in second year the students can-opt for their major subject. In 2015, only 80% of the students passed the first year examination and all of those who passed joined in the second year. In 2015, only 20% of students of first year who passed the first year examination joined physical sciences, 30% joined the Arts stream, 40% joined commerce stream while others joined computer stream. Apart from those, some students from other universities who passed their first year also joined Chennai Anna University. Such students were 30% of the number of first year students from Chennai Anna University who passed 2015 examination. The number of students from other universities across physical sciences, Arts, commerce and computer streams are joined in Chennai Anna University were in ratio 1: 3: 4: 2 respectively. In 2015, the number of students in Arts stream in Chennai Anna University in second year was 780.**

*17. In 2015, what percent of science stream students in second year in Chennai Anna University were first year science stream students who pass-outs from Chennai Anna University only? (Approximately)*

*(A) 87%*

*(B) 83%*

*(C) 92%*

*(D) 77%*

*(E) 73%*

*18. What is the total number of students promoted to second year?*

*(A) 2500*

*(B) 2250*

*(C) 2000*

*(D) 1500*

*(E) 1750*

*19. What is the total number of students studying in Chennai Anna University in second year?*

*(A) 2000*

*(B) 2600*

*(C) 2300*

*(D) 2700*

*(E) 2400*

*20. What was the number of students in second year commerce stream in Chennai Anna University in 2015?*

*(A) 1040*

*(B) 1080*

*(C) 1050*

*(D) 1150*

*(E) 1200*

*21. What is the number of students from other universities joining Chennai Anna University in 2015?*

*(A) 500*

*(B) 600*

*(C) 800*

*(D) 400*

*(E) 1000*

**Aspirants can check the answers for the above Questions from the below given ones. **

**1. (b) **

*Only two languages (One is COBOL)= 1200- (404+388+222+40+74)= 72*

**2. (a) **

*COBOL+BASIC and COBOL+C = 1200- (404+388+222+40+74)= 72*

*Exactly any two languages only = = 72+74 = 146*

**3. ( b ) **

*COBOL+BASIC and COBOL+C = 1200- (404+388+222+40+74)= 72*

*C language= 404+74+40+(72-COBOL language and BASIC only)=554*

*Therefore, COBOL+BASIC =( 404+74+40+72)-554=36*

*Required total = 222+74+40+36 = 372*

**4. (e) **

*BASIC language = 222+74+40+(BASIC and COBOL only)=384*

*BASIC and COBOL only=384-(222+74+40)=48*

*Therefore, COBOL and C only=72(BASIC and COBOL only + COBOL and C only) – 48=24*

*Both COBOL and C = 40+24=64*

**5. (c) **

*Number of students study C and BASIC language = Total-COBOL only*

*=1200-388=812*

**6. (a)**

*Dhoni:*

*Let the distance between his house and school be Y km*

*Time taken when he walks at 6 km/hr = Y/6*

*Time taken when he walks at 8 km/hr = Y/8*

*In the first case he is late by 8 minutes while in the second case he reaches early by 8 minutes. So, time difference = 16 minutes.*

*So, we have, *

*Y = 6.4 km*

**7. (a) **

*Dhoni:*

*Let the distance between his house and school be Y km*

*Time taken when he walks at 6 km/hr = Y/6*

*Time taken when he walks at 8 km/hr = Y/8*

*In the first case he is late by 8 minutes while in the second case he reaches early by 8 minutes. So, time difference = 16 minutes.*

*So, we have, *

*Y = 6.4 km*

*Dhoni needs to cover 6.4 km*

*In 1st case he walks at 6 km/hr*

*Required time = = 64 minutes*

*Therefore, 8 minutes late, = 64-8 = 56 minutes.*

*Required speed =*

*Kohli:*

*Let the distance between his house and school be Z km*

*Time taken when he walks at 6.5 km/hr = Z/6.5*

*Time taken when he walks at 8 km/hr = Z/8*

*In the first case he is late by 12 minutes while in the second case he reaches early by 6 minutes. So, time difference = 18 minutes.*

*So, we have, *

*Z = 10.4 km*

*In 2nd case he walks at 8 km/hr*

*Required time == 78 minutes*

*Therefore, 6 minutes late, = 78+6 = 84 minutes.*

*Required speed = *

**8. (d) **

*Kohli:*

*Let the distance between his house and school be Z km*

*Time taken when he walks at 6.5 km/hr = Z/6.5*

*Time taken when he walks at 8 km/hr = Z/8*

*In the first case he is late by 12 minutes while in the second case he reaches early by 6 minutes. So, time difference = 18 minutes.*

*So, we have, *

*Z = 10.4 km*

**9. (a) **

*water: milk = 4: 5*

*Mixture D is obtaining by mixing B and C in the ratio 1: 3*

*Let x litres of B and 3x litres of C be mixed.*

**10. ( d) **

*water: milk = 4: 5*

*Required ratio= 5:2*

**11. (c) **

*water: milk = 4: 5*

*Mixture D is obtaining by mixing B and C in the ratio 1: 3*

*Let x litres of B and 3x litres of C be mixed.*

*Required ratio= (1/8 ) : (1/18) =18:8=9:4*

**12. (c) **

*The total number of students who are interested in both painting and singing =240×(6/5)=288*

*The number of students interested in all the three activities = (5/8)×288= 180*

*Number of students who are interested in only painting and singing but not in dancing = 288-180 = 108*

*The number of students interested in both singing and dancing but not painting = (240+180)/2 = 210*

*The number of students who are interested in only dancing = 210×1.3= 273*

*Let, the number of students interested in only singing = x*

*Let, the number of students interested in both dancing and painting but not singing = y*

*108+180+210+x = 210+180+y+273*

*x-y = 165*

*Also,*

*108+180+y+ 210 = 2x*

*498+y=2x*

*Y = 2x-498*

*x-2x-498 = 165*

*498-165 = x*

*333 = x*

*Y = 168*

*Required total = 240+108+168+180+210+273+333 = 1512*

**13. (b) **

*The total number of students who are interested in both painting and singing =240 × (6/5)=288*

*The number of students interested in all the three activities = (5/8) × 288= 180*

*Number of students who are interested in only painting and singing but not in dancing = 288-180 = 108*

*The number of students interested in both singing and dancing but not painting = (240+180)/2 = 210*

*The number of students who are interested in only dancing = 210×1.3= 273*

*Let, the number of students interested in only singing = x*

*Let, the number of students interested in both dancing and painting but not singing = y*

*108+180+210+x = 210+180+y+273*

*x-y = 165*

*Also,*

*108+180+y+ 210 = 2x*

*498+y=2x*

*Y = 2x-498*

*x-2x-498 = 165*

*498-165 = x*

*333 = x*

*Y = 168*

*Required % =*

**14. (d) **

*The total number of students who are interested in both painting and singing =240× ( 6/5)=288*

*The number of students interested in all the three activities =( 5/8 ) ×288= 180*

*Number of students who are interested in only painting and singing but not in dancing = 288-180 = 108*

*The number of students interested in both singing and dancing but not painting = (240+180)/2 = 210*

*The number of students who are interested in only dancing = 210×1.3= 273*

*Let, the number of students interested in only singing = x*

*Let, the number of students interested in both dancing and painting but not singing = y*

*108+180+210+x = 210+180+y+273*

*x-y = 165*

*Also,*

*108+180+y+ 210 = 2x*

*498+y=2x*

*Y = 2x-498*

*x-2x-498 = 165*

*498-165 = x*

*333 = x*

*Y = 168*

*Required difference = 273+210-(240+108)=135*

**15. (e) **

*The total number of students who are interested in both painting and singing =240× (6/5)=288*

*The number of students interested in all the three activities = (5/8) ×288= 180*

*The number of students interested in both singing and dancing but not painting = (240+180)/2 = 210*

*The number of students who are interested in only dancing = 210×1.3= 273*

*Let, the number of students interested in only singing = x*

*Let, the number of students interested in both dancing and painting but not singing = y*

*108+180+210+x = 210+180+y+273*

*x-y = 165*

*Also,*

*108+180+y+ 210 = 2x*

*498+y=2x*

*Y = 2x-498*

*x-2x-498 = 165*

*498-165 = x*

*333 = x*

*Y = 168*

*Required total = 108+168+210 = 486*

**16. (a)**

*The total number of students who are interested in both painting and singing =240× (6/5)=288*

*The number of students interested in all the three activities = (5/8) ×288= 180*

*The number of students interested in both singing and dancing but not painting = (240+180)/2 = 210*

*The number of students who are interested in only dancing = 210×1.3= 273*

*Let, the number of students interested in only singing = x*

*Let, the number of students interested in both dancing and painting but not singing = y*

*108+180+210+x = 210+180+y+273*

*x-y = 165*

*Also,*

*108+180+y+ 210 = 2x*

*498+y=2x*

*Y = 2x-498*

*x-2x-498 = 165*

*498-165 = x*

*333 = x*

*Y = 168*

*Required total = 273*

**17. (a)**

*Let us assume the total number of first year students in Chennai Anna university be X*

*Then, as per data, number of students who passed in first year = 0.8X*

*Students in physical science, commerce, arts and computer stream becomes: 0.16X, 0.32X, 0.24X, 0.08X respectively.*

*Total number of students from other universities = 30% of 0.8X = 0.24 X*

*Ratio of students from other universities in different streams is*

*Physical Science = 0.024X, Arts = 0.072X, Commerce = 0.096X, computer = 0.048X*

*Given that number of students in arts stream = 780*

*Therefore,*

*0.072X+ 0.24X = 780*

*X= 2500*

*Hence, total number of students in first year = 2500*

*Total students in promoted to second year = 2000*

*Students from other Universities joining Chennai Anna University = 0.24X = 600*

*Total students studying in Chennai Anna University in second year = 2000+ 600 = 2600*

*Total science students in Chennai Anna University = 0.16x+0.024x = 460*

*First year pass- outs of Chennai Anna University joining science stream = 0.16X = 400*

*Required % = (400/460)×100=87%*

**18. (c)**

*Let us assume the total number of first year students in Chennai Anna university be X*

*Then, as per data, number of students who passed in first year = 0.8X*

*Students in science, commerce, arts and computer stream becomes: 0.16X, 0.32X, 0.24X, 0.08X respectively.*

*Total number of students from other universities = 30% of 0.8X = 0.24 X*

*Ratio of students from other universities in different streams is*

*Science = 0.024X, Arts = 0.072X, Commerce = 0.096X, computer = 0.048X*

*Given that number of students in arts stream = 780*

*Therefore,*

*0.072X+ 0.24X = 780*

*X= 2500*

*Hence, total number of students in first year = 2500*

*Total students in Anna University promoted to second year = 2000*

**19. (b) **

*Let us assume the total number of first year students in Chennai Anna university be X*

*Then, as per data, number of students who passed in first year = 0.7X*

*Students in Physical science, commerce, arts and computer stream becomes: 0.16X, 0.32X, 0.24X, 0.08X respectively.*

*Total number of students from other universities = 30% of 0.8X = 0.24 X*

*Ratio of students from other universities in different streams is*

*Physical Science = 0.024X, Arts = 0.072X, Commerce = 0.096X, computer = 0.048X*

*Given that number of students in arts stream = 780*

*Therefore,*

*0.072X+ 0.24X = 780*

*X= 2500*

*Hence, total number of students in first year = 2500*

*Total students in promoted to second year = 2000*

*Students from other Universities joining Chennai Anna University = 0.24X = 600*

*Total students studying in Chennai Anna University in second year = 2000+ 600 = 2600*

**20. (a) **

*Let us assume the total number of first year students in Chennai Anna university be X*

*Then, as per data, number of students who passed in first year = 0.8X*

*Students in Physical science, commerce, arts and computer stream becomes: 0.16X, 0.32X, 0.24X, 0.08X respectively.*

*Total number of students from other universities = 30% of 0.8X = 0.24 X*

*Ratio of students from other universities in different streams is*

*Physical Science = 0.024X, Arts = 0.072X, Commerce = 0.096X, computer = 0.048X*

*Given that number of students in arts stream = 780*

*Therefore,*

*0.072X+ 0.24X = 780*

*X= 2500*

*Hence, total number of students in first year = 2500*

*Total students in Anna University promoted to second year = 2000*

*Students from other Universities joining Chennai Anna University = 0.24X = 600*

*Total students studying in Chennai Anna University in second year = 2000+ 600 = 2600*

*Total number of students in commerce stream in 2015 = 0.32X+0.096X = 0.416X = 1040*

**21. ( b )**

*Let us assume the total number of first year students in Chennai Anna university be X*

*Then, as per data, number of students who passed in first year = 0.8X*

*Students in science, commerce, arts and computer stream becomes: 0.16X, 0.32X, 0.24X, 0.08X respectively.*

*Total number of students from other universities = 30% of 0.8X = 0.24 X*

*Ratio of students from other universities in different streams is*

*Science = 0.024X, Arts = 0.072X, Commerce = 0.096X, computer = 0.024X*

*Given that number of students in arts stream = 780*

*Therefore,*

*0.072X+ 0.24X = 780*

*X= 2500*

*Hence, total number of students in first year = 2500*

*Total students in promoted to second year = 2000*

*Students from other Universities joining Chennai Anna University = 0.24X = 600*

*Total students studying in Chennai Anna University in second year = 2000+ 600 = 2600*

**SBI PO Prelims Exam Analysis & Review 2018 8th July (All Shifts)**

**SBI PO Prelims Exam Analysis & Review 2018 8th July (All Shifts)**