# New Pattern Inequality Quiz For Upcoming Exams Answers

 All Exams Free Study Material and PDFs Join Our Telegram Channel Click Here Join Now

Solutions

Q1 Option D

Quantity1:

Total weight of 11 persons = 42*11 =462

Total weight of first 5 persons = 36*5 = 180

Total weight of last 5 persons = 41*5 =205

Weight of 6 one = 462- (180+205) = 77kg

Quantity 2:

Average of five consecutive odd numbers = 45(It should be a middle number) <=(If the difference is equal, then the middle no will be your average value)

So, the series must be

41, 43,45,47,49

Sum of first and last number = 49+41= 90 kg

Quantity I < Quantity II

Q2 Option C

Quantity1:

Total cost price = 15000+1000 =16000

Selling price = 20000

Profit = 20000-16000 =4000

Quantity2:

Cost price of an article = sp –profit

= 2500-250 = 2250

Quantity I > Quantity II

Q3 Option C
Quantity1:

50km in half an hour

Speed = 100km/hr

60 -100

225 – ?

Total distance travelled = 375km

Quantity2:

Quantity I > Quantity II

Q4 Option B

Quantity1:

Quantity 2:

Quantity I ≥ Quantity II

Q5 Option C

Quantity1:

Area of circle,

=

r = 110.25

r = 10.5 m

Circumference =

Total cost = 66*27.5 = Rs.1815

Quantity 2:

Investment ratio = 7: 8

Total investment ratio = 7*9: 8*12 = 63: 96 = 21:32

A’s profit =

Quantity I > Quantity II

Q6.Option D

Quantity1:

Speed =207 *(5/18) =57.5m/s

Time = (650/57.5) =11.3 sec

Quantity 2:

Speed of Train A = 250/25 = 10m/sec

Time taken to cross each other = (250+320) / (25+10) = 16.28sec

Quantity I < Quantity II

Q7 Option D

5 years ago, A_B= 8:5 (we assume this as 8x and 5x)

2 years hence, A_B= 5:4

32x+28= 25x+35

7x=7

=>x=1

The present age of Suba= 8x+5 =13 years

Quantity 2:

After 5 years, A_B= 3:4 (we assume this as 3x and 4x)

4 years hence, A_B= 29:39

3x-1/4x-1 = 29/39

117x-39=116x-29

=>x= 10

The present age of A= 3x-5 = 25 years

Quantity I < Quantity II

Q8 Option D

Quantity 1:

Average of first 10 odd number = (1+3+5+7+9+11+13+15+17+19)/10=10

(or)

If the difference is equal, then the average will be the middle number. Here the middle no is 9 and 11. So, the average is (9+11)/2 = 20/2=10

Quantity 2:

Average of first 10 prime number = (2+3+5+7+11+13+17+19+23+29) =129/10 =12.9

Quantity I < Quantity II

Q9 Option C
Quantity 1:

1/7 -1/9 = 9-7 / (9*7) = 2/63 = 1/31.5

Total time taken = 31.5 hrs

Quantity 2:

One tap can fill tank in 6 hours and another tap can fill the tank in15 hours

The total capacity of the tank is 30. (ie., LCM of 6 and 15)

Total hours per hour capacity

Tap 1=> 6          5

Tap 2=> 15        2

Both tap are opened alternatively.

The first two hours the capacity of tap 1 and 2 is 7. So, 7*4= 28(8 hour capacity)

Remaining 2 will be there. Remaining will be filled by tap 1. So, 2/5 hr

The tank will be filled in  hrs

Quantity I > Quantity II

Q10 Option D
Quantity1:

Probability = 4C2 /52C2 = 6/(26*51) = 1/221

Quantity 2:

Total Probability = 6 =36

Divisible by 2 = 18 possibilities

Probability = 18/36 = 1/2

Quantity I < Quantity II