## Quant Quiz On Time & Work Day 12 Bag

• A is thrice as good a workman as B and therefore able to finish a job in 48 days less than B working together ,they can do it in how many days together ?
A) 13 days
B) 15 days
C) 18 days
D) 12 days
E) 116 days

Option  C
Solution:
.                   A:B
Efficiency=3:1
Time=1:3
Multiplying by 24 on both the sides ,
A’s=24 days
B’s=72 days
Therefore,2 units =48 days
1 units =24 days
Total work=No. of days *Efficiency
.                                       72*1
.                                        =72
One day work of A and B is 3+1=4 units
A and B will complete the work in =72/4=18days.
• Three men –A ,B and C working together can do a job 6 hours less time than A did alone ,1 hour less time than B alone and half the time needed by C .In how many days will A finish the work alone ?
A) 20/3 days
B) 23/4 days
C) 22/5 days
D) 33/6 days
E) 27/8 days

Option A
Solution:
A+B+C          A           B            Cx hr.            x+6       x+1       2xTaking LCM = 2x (x+1)(x+6)
Taking efficiency of A and B ;
2x(x+1)(x+6)/(2x2 +2x+2x+12x)        = 2x/1
3x+7x-6=0
X=-3(ignore)
X=2/3
A will finish its work in (x+6)=20/3 days
• A work is started by a man on the first day. Each subsequent day a new person joined the work and it is known that the total work will completed on the 11th day. If from the starting day 6 men working on that work and no new men added later, in how many days the work got completed?
A) 15 days
B) 12 days
C) 14  days
D) 11 days
E)  None of these.

Option D
Solution:
1day work of a man is 1 unit. If a new person joined the work on second day, 2 units of work get completed. Similarly 3 units on 3rd day, 4 units on 4th day so on…
Then for all the eleven days the total work = 1 + 2 + 3+ ………….11 = 66 units (Use formula
N(N+1)/2)
Now 6 men /day work = 6 units/day.
They can complete 66 units of work in =
66/6
=11 days
• Two men can complete a piece of work in 3 days while 3 women can complete the same work in 4 days and 4 children can complete the same work in 6 days. Then find in how many days 1 men ,1 women and 2 children can complete the same work ?
A) 4 days
B) 3 days
C) 5 days
D) 2 days
E) None of these.

Option B
Solution:
2M *3 = 3W*4 = 4C*6
.      1M =  2W =   4C
LCM=4
1 Man’s efficiency= 4units/day
2 Women’s efficiency=2units/day
4 Children’s efficiency= 1 units/day
Total work =(2*4)*3=24 days
(1man+1woman+2children)=4+2+2=8
(1man+1woman+2children) complete the work =24/8=3 days
• 30 men are supposed to do a work in 38 days. After 25 days, 5 more men were employed on work for which the work is completed in 1 day before . If 5 more men were not worked then how many days took in delay?
A) 1 day
B) 2 days
C) 3 days
D) 4 days
E) None of these.

Option A
Solution:
30Men * 25 days = 750
35 Men * 12 Days = 420
Total =750+420=1170
Now,1170/30 =39 days
1 day delay
• A group of men decided to do a job in 4 days but 20 men dropped out everyday ,the job was completed at the end of the 7th day .Find the men who are in the work initially ?
A) 155
B) 135
C) 120
D) 140
E)  160

Option D
Solution:
Total work = M * 4 = 4M
M + (M+20) +…….
7/2 [2M +6(-20)] =4M
M=140
• A printer A can print one thousand books in 15 hours ,printer B can print the same number of books in 10 hours and printer C can print the same number of books in 12 hours . If all the printers are started to print the books at 8 A.M, After sometime printer A is closed at 9 A.M and printer B and printer C remains working. Find at what time the printing will be completed ?
A) 4(3/11)hours
B) 3(1/11)hours
C) 5(1/11)hours
D) 3(5/11)hours
E) None of these.

Option C
Solution:
Let printing completed in be T hours
Then A ‘s 1 hour work ,B’s T hours work and C;s T hours work =Total work
1/15 +T/10+T/12 =1
T= 5(1/11)
Hence ,the printing of books will be completed at 5(1/11)hours
• Ramesh and Ram can do a piece of work in 24 and 30 days respectively. They both started and worked for 6 days. Ram then leaves the work and another their friend Rohit joins the work and completed the remaining work with Ramesh in 11 days . Find how many days are taken by Rohit alone to finish the work?
A) 110 days
B) 132 days
C) 150 days
D) 120 days
E) None of these.

Option D
Solution:
(1/24 + 1/30) *6 +(1/24 + 1/Rohit ) *11 = 1
Therefore ,Rohit takes 120 days to finish the work.
• A woman has her three daughters. First and second can take 24 and 30 days resp. to complete a work .In how many days third one takes to complete the work. If woman can complete the whole work alone in 3(3/11) days .The efficiency of woman is double than her three daughters.
A) 22 days
B) 12 days
C) 13 days
D) 21 days
E) 19 days

Option B
Solution:
LCM = 72 (if we are taking woman and her two daughters )
Here it is given
Woman Three daughters
Time taken = 1 : 2
Efficiency= 2 : 1Three daughters, let P +Q+R=11
3+2+R=11
R=6 days
Her third daughter complete the work in =72/6= 12 Days
• A contractor takes a road construction project to finish it in 40 days and for that he engaged 200 men. After 30 days he employed 100 more men in this project, then the work finished on time. Find if the 100 more men would not worked then how many more days required to finish the work ?
A) 8 days
B) 10 days
C) 12 days
D) 7 days
E) None of these.

Option E
Solution:
100 * 10 days = 1000
Now 1000/200 = 5 days (Initial total no. of men engaged in the project)
Hence ,5 more days required to finish the work if 100 more men would not joined .

• A cistern can be filled by two pipes separately in 6 and 9 mins respectively. Both pipes are opened together for a certain time but being clogged, only 5/6 of full quantity water flows through the first and only 3/4 through the second pipe. The obstructions, however, being suddenly removed, the cistern is filled in 2 mins from that moment. How long was it before the full flow began?
A) 3 min
B) 2 min
C) 1 min
D) 2.5 min
E) 1.5 min

Option  B
Solution:
total units …….36
first pipe ………36/6 = 6 units
second………….36/9 = 4units
now, ( 5/6 * 6 + 3/4* 4 ) T + 2 ( 6+4 ) = 36 >> T =2
• Ram and mohan together can complete typing a book of 1575  pages in 25  days working 15 hrs per day. Ram is 20% more efficient than Mohan. A page contains an average of 275 words, then how many words can ram type in an hour?
A) 525
B) 600
C) 625
D)630
E) 645

Option D
Solution:
Ram : mohan = 6:5
R+M = 11
R+M = 1575 * 275 / 15* 25 = 1155 words in 1 hour
ram will type = 1155 * 6/11 = 630 words in 1 hour
• Subhash can copy 70 pages in 16 hours ; Subhash and Prakash together can copy 275  pages in 40 hours. In how much time can Prakash copy 30 pages ?
A) 15 hr.
B) 12 hr.
C) 14  hr.
D) 18 hr.
E)  None of these.

Option B
Solution:
Subhash can copy 70 pages in 16 hours so In 40 hours he can copy 70*2.5 = 175 pages. Hence prakash can copy 100 pages in 40 hours . Thus , he can copy 30 pages in 30% of the time i.e 12 hours.
• A and B together can do a piece of work in 12 days which B and C together can do in 16 days. After A has been working at it for 5 days and B for 7 days, C finishes it in 13 days. In how many days could each do the work by himself ?
A) 24, 12, 36
B) 24, 16, 12
C) 16, 48, 24
D) 24, 36, 12
E) None of these.

Option C
Solution:
Total work  = 48 ,… A+B = 4 ….B+C = 3
now, 5A + 7B + 13C = 48
split it
5A +5B + 2B + 2C + 11C = 48
so 5*4 + 2*3 + 11c = 48
so 11c = 22 …… c = 2
so c alone = 48/2 = 24
A — 48/3 = 16
B— 48/1 =48
• 24 men take 12 days to complete a piece of work . They worked for a period of 4 days . After that , they were joined by 8 more men . How many more days will be taken by them to complete the remaining work?
A) 8 days
B) 9 days
C) 7 days
D) 6 days
E) None of these.

Option D
Solution:
24*12 – 24*4 =( 24+8 )x
By solving we get x = 6 days
• In two days A, B and C together can finish 1/4 of a work and in another 2 days B and C together can finish 1/5 part of the work. Then A alone can complete the whole work in?
A) 10 days
B) 20 days
C) 40 days
D) 35 days
E)  None of these.

Option C
Solution:
work ……. 20
a+b+c = 5 in 2 days
b+c = 4 in 2 days
a = 1 in 2 days >> 40 days total
or
2(a+b+c) =1/4 =>a+b+c =1/8
2(b+c) =1/5 =>b+c =1/10 >  a =1/8-1/10 =1/40 =40 days
• A team of 100 men is supposed to do a work in 60 days. After 35 days, only 5/12 of the work was completed, so to complete the work before 40 more men were employed. If 40 men were not employed, how many extra days were required to complete the work by earlier number of men?
A) 11 days
B) 15 days
C) 12 days
D) 14 days
E) None of these.

Option D
Solution:
100 men completed 5/12 work in 35 days
So 100 men can complete the remaining 7/12 work in 49 days:
Use M1*D1*W2 = M2*D2*W1
100*35*(7/12) = 100*D2* (5/12)
D2 = 49 days
But after 35 days, 40 more men were employed, so 140 men now and they completed 7/12 work in
By M1*D1*W2 = M2*D2*W1
100*35*(7/12) = 140*D2*(5/12)
D2 = 35 days
So extra days = 49-35 = 14 days
• Two typist of varying skills can do a job in 6 minutes if they work together. If the first typist typed alone for 4 minutes and then second typed for 6 minutes , they would be left with  1/5 of the whole work. How many minutes would it take the slower typist to complete the work alone ?
A) 10 min
B) 12 min
C) 15 min
D) 20 min
E) None of these.

Option C
Solution:
The first typist types for 4 minutes and second one for 6 minutes , the work left would be the work the first typist can do in 2 minutes. Thus the time taken by the first typist to do the work would be 10 minutes and his rate of work would be 10% per minute . Since both can do whole work in 6 minutes their combined efficiency = 100/6 = 16.66% > second typist = 6.66%
so he would take = 100/6.66 = 15 minutes.
• Tap A  can fill a tank with water in 10 hrs. Tap B fills the same tank with milk in 12.5 hrs. A man who wanted to fill the tank with the mixture opens tap A first , which already contains 8% milk of its own capacity. After two hours he opened tap B till the tank gets filled completely. In what proportion should he mix this solution with the other one containing water and milk in the ratio 2 : 3, so that the new solution will contain half milk and half water?
A) 2:3
B) 1:1
C) 1:2
D) 2:1
E) 1:3

Option B
Solution:
Total work  – 50
a== 5
b== 4
it already contain 8% milk = 4 lit
a—- in 2 hrs = 5*2 = 10 lit water
so, total fill = 14 lit. remain. = 36 lit
done by a+b in 36/9 = 4 hrs
so,water added by a — 4*5 = 20 litre
milk added by b —- 4*4 = 16 litre
so. Total water ==== 10 + 20 = 30 litre
Total milk ===== 4 + 16 === 20 litre
W:M = 3:2
now 3/5______________2/5
____________1/2_______1:1
• A, B, C complete a work in 15, 20 and 30 days . They work together for sometime after which C left. A total of 18000 rs is paid for the work and B gets 6000 rs more than C.For how many days did A work ?
A) 8 days
B) 10 days
C) 12 days
D) 7 days
E) None of these.

Option A
Solution:
Total work  = 60
A — 4 ,, B– 3 ,,,, C — 2
let A &B work for x days
Then work done by A = 4x
B = 3x
C =60- (4x+3x)
So ratio of their share
4x : 3x : 60-7x
Difference between b and c = 3x – (60-7x) = 10x – 60
( 10x – 60)/60 * 18000 = 6000
so,x =8

• B takes twice time as A to complete a work and C takes thrice time as B to complete a work. If Rs6000 is given to them to complete a work together then B gets how much amount?
A) Rs1800
B) Rs3600
C) Rs600
D) Rs3000
E) Rs1200

Option A
Solution:

.               B……A              B…….A
.               2…….1               1………3
Days                     A…..B…….C
.                             1…….2……6
Efficiency             6…….3…..1
.                              3/10*6000 =1800
• A & B can do a piece of work in 80days. B & C can do same work in 50days and C & A can do same work in 60days. Find in how many days they all together can complete that work?
A) 40 (40/59)
B) 60 (40/59)
C) 36 (40/59)
D) 25 (40/59)
E) 26 (40/59)

Option A
Solution:

LCM = 2400
A + B = 80………….2400/80 = 30
B + C = 50…………………………..48
C + A = 60…………………………..40
2(A + B + C) = 118
A+ B + C = 59
So 2400/59  days
• A & B separately can do a piece of work in 9days and 12days respectively. If they work for a day alternatively, A starts the work, in how many days will the work will get completed?
A) 12(1/4)
B) 10(1/4)
C) 8(1/6)
D) 10(5/6)
E) 9(1/6)

Option B
Solution:

A=9        4
B=12      3          [LCM=36]
2 days alternate            (4+3) = 7 days
2*5                                    7*5
10days                             35days
now A’s turn so-  10(1/4) days
• 4men and 6boys earn Rs1600 in 5days, 3men and 7boys earn Rs1740 in 6days, in what time will 7men and 6boys earn Rs3760?
A) 4days
B) 6days
C) 8days
D) 10days
E) 5days

Option C
Solution:

4M + 6B= 1600/5=320……………(1)
3M + 7B= 1740/6=290……………(2)
FROM EQUATION (1) AND (2) WE GET
(4*7)B – (3*6)B = 290*4 – 320*3
B = Rs20……put in (1)
M = Rs50
now required number of days
3760/(7*50+6*20) = 3760/470 = 8days
• A tap take 42hrs extra to fill a tank due to a leakage equivalent to half of its inflow. The inlet pipe alone can fill the tank in how many hour?
A) 42hrs
B) 21hrs
C) 36hrs
D) 28hrs
E) 30hrs

Option A
Solution:

.               Without leak……………………With leak
Efficiency             2………………………….1
Time                      1…………………………..2
.                                          +1 == 42hours
So 42hours
• A tank can be filled with two pipes in 30minutes and 45minutes. When the tank was empty the two pipes A and B were opened. After some time, the first pipe A was closed and the tank was filled in 24minutes. After how much time from the start was the first pipe A closed?
A) 16 days
B) 15 days
C) 14 days
D) 12 days
E) 10 days

Option C
Solution:

A = 30, B = 45
LCM = 90
So, A = 90/30 = 3
. B = 90/45 = 2
B worked for all 24 days means did 24*2 = 48 units work
Remaining work = 90-48 = 42
This work is done by A, so 42/3 = 14 days
• A boy and a girl together fill a cistern with water. The boy pours 3ltr of water in every 2minutes and the girl pours 2ltr of water in every 3minutes. How much time will it take to fill 91ltr of water in the cistern?
A) 36min
B) 42min
C) 48min
D) 44min
E) 45min

Option B
Solution:

boy 2min = 3ltr
girl 3min = 2ltr
make time same
6min………..13ltr
*7…………….*7
42min………91ltr
• A and B together can complete a work in 30days and B alone can do it in 60days. Find in how many days A alone can do the work?
A) 40
B) 60
C) 120
D) 90
E) 110

Option B
Solution:

A+B…30……2
B……60……1……………(LCM=60)
A  ……………1
A = 60/1 = 60
• A and B can do a work in 18days. They started together but after 8days A left the work. If B does the remaining work in 20days, then in how many days A will do the work alone?
A) 18
B) 24
C) 36
D) 48
E) 50

Option C
Solution:

. A+B = 18
Let total work  =18
1day work of A & B=1
8days work of A&B =8
remaining =18 -8 =10
B does 10 work in 20days
So     18 work in 36days
A+B= 18
B      =36
LCM = 36
A+B= 18……..36/18 =2
B      =36………36/36 = 1
So A= 1
So days A   = 36/1   = 36
• A can write 75pages in 25hrs. A and B together can write 135pages in 27hrs.  In what time can B write 42pages?
A) 17
B) 19
C) 23
D) 21
E) 20

Option D
Solution:

A can write 75/25 =3pages in 1hr
A+B can  135/27 = 5pages in 1hr
B can write 5-3 = 2page in 1hr
42/2 =21hrs

• A & B can separately finish the work in 30 days and 50 days respectively. They worked together and A left the work, so B complete the remaining work in 10 days. Find after how many days A left the work?
A) 10days
B) 12days
C) 15days
D) 20days
E) 18days

Option C
Solution:

A = 30………..5
B = 50……….3    (LCM = 150)
A+ B = 8
B’s work in 10days = 3*10 =30
Means they together did ……120
120/8= 15days
• A is 20% more efficient than B and 50% more efficient than C. if they together can do a work in 24 days then find in how many days B alone can do the work?
A) 60days
B) 72days
C) 90days
D) 180days
E) 100days

Option B
Solution:

.                  A ………B   |   A………C
Efficiency    6……….5    |   3………2
Days            5……….6   |   2………3
Days A : B : C
.        10 12 15
A = 10……….6
B = 12………..5 ….        (LCM = 60)
C = 15………..4
A+B+ C = 15
60/15=4
4=24
1= 6
B=12= 12*6 = 72days
• A can make 10000 papers in an hour B can make 8000 papers in an hour. Find in how many days they both can make 5,90,000 papers, if A do work for 7 hours and B do work for 6 hours?
A) 4days
B) 3days
C) 5days
D) 6days
E) 7days

Option C
Solution:
A’s 1hr work = 10,000
7hr work = 70,000
B’s 1hr work = 8000
6hr work = 48,000
Total work of A& B of 1day = 70,000+48,000= 1,18,000
So 590000/118000 = 5days
• 7 men and 5 women can do a work in 6 days. Also 6 men and 7 women can do same work in 6 days. Find in how many days will 2 men & 2 women can finish the work?
A) 19days
B) 15days
C) 10days
D) 14days
E) 22days

Option A
Solution:

7M + 5W =6
42M+30W = 1……………….(1)
6M +7W =6
36M + 42W =1……………..(2)
FROM (1) & (2)
. 42M + 30W =1
-36M (-)+ 42W =(-)1
6M -12W =0
6M =12W
M =2W…….PUT IT IN EQUATION(1)
S0 .. 14W +5W= 6
19W =6
1W = 6*19
6W = 6*19/6 =19DAYS
• A & B can do a work in 18 days. They started work together and A left after 7 days and B did the remaining work in 33 days. Find in how many days A can alone do the work?
A) 18
B) 54
C) 27
D) 36
E) 32

Option C
Solution:

let total work = 18
Efficiency of A &B’s work of 1day =1
In 7days they complete =7 work
Remaining = 18-7 = 11
B do 11 work = 33 days
1 work = 3days
18work = 54days
So ……. A+B = 18…….3                (LCM = 54)
.                 B = 54……..1
So A = 3-1 = 2
A = 54/2 =27days
• A tap can fill a tank in 16 hrs but due to a leak it takes 6 hrs more. If leakage withdraw 9ltr water in an hour than find the quantity of tank?
A) 520ltr
B) 528ltr
C) 536ltr
D) 544ltr
E) 576ltr

Option B
Solution:

A = 16 ………….11                (LCM = 176)
A+B=22 …………8
So B = 11-8 = 3
176/3 * 9= 528ltr.
• A & B can do a work in 35 days and 45 days respectively. They worked for 10 days and after then they complete the work with the help of C in 15 days. If they all get Rs 770. Then find the share of C?
A) 330
B) 270
C) 190
D) 170
E) 250

Option D
Solution:

A = 35…………..11          (LCM = 385)
B = 45……………9
A+B=20
20*10 =200
Remaining 385-200=185
This work is completed in 5days. So 185/5=37
A&B 5days work = 20*5=100
C’s 5days work =85
A………….B………………C
11*15     9*15              85
165         135               85
33            27                17
C’s share = 17/77  * 770 = 170
• 1 man or 2 women or 3 children can do a work in 55 days. Find in how many days 1 man and 1 woman and 1 child can do the work?
A) 30days
B) 24days
C) 25days
D) 28days
E) 32days

Option A
Solution:

1M = 55   1
2W =55    1            55
2C =55     1
We need 1day work of … 1M +1W+1C= 1+1/2+1/3 =11/6
So …….. 55/(11/6) = 55/11 * 6=30 DAYS
• A can a work in 50 days and B is 50% efficient than A. find in how many days A and B together can complete the work?
A) 30
B) 40
C) 50
D) 33(1/3)
E) 16(2/3)

Option D
Solution:

B is 50% efficient than A
.                   A………..B
Efficiency      2……….. 1
Days             1…………2
1 == 50  . So 2 == 100
A= 50……….2               (LCM = 100)
B =100………1
A+ B = 3
100/3 =33(1/3) days.
• A and B can do a work in 60days. B and C can do same work in 40 days and C and A can do same work in 50 days. Find in how many days will A,Band C work together will finish the work?
A) 32(16/37)
B) 42(14/37)
C) 33(7/37)
D) 43(9/37)
E) 39(7/37)

Option A
Solution:

A+B = 60…………10
B+C = 40………….15…………….(LCM =.600)
C+A = 50………….12
2(A+B+C)            37
A+B+C = 37/2
= 600/37 * 2 = 32(16/37)