# Solution

1. c
Vanita’s present age = 39 – 4 = 35 years
So, Tanu’s present age = 15 years
Tanu’s age 6 years ago = 9 years

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The sum of the ages of two new girls years Average yr

3. d
Suppose, present age of Reema = years
And of Komal years
According to question,    x = 69

4. e
Let be age is x

Sum of their ages 6x + 4x + 7x = 34
17 x = 34
x = x = 2

Mira’s age = 6x = 6×2 = 12
Tina’s age = 4x = 4×2 = 8
Sania’s age = 7x = 7×2 = 14

5. e
Let Michelle present age is = X
Therfore according to problem,
(X-9) x 4/3 = X
X= 36
Now her daughter’s age is 1/6th of her age = 36 x 1/6 = 6
Therefore 2 years ago her daughter’s age is = 4 years

6. e
Let Ritu’s present age be x. As per question, x = (2* (x-12)) – 3, x = 27 years
Also, (Raj’s present age) : Ritu’s present age = 4 : 9, Raj’s present age = 4/9 * 27 = 12 years
Raj’s age after 5 years = 12 + 5 = 17 years.

7. e
Rakhi’s present age = 5x years
Sita’s present age = 7x years
After 8 years,
5x + 8 = 28  Sita’s age 5years ago = 7x – 5
= 7 × 4 – 5 = 23 years

8. c
Suppose the present age of Melwyn and Louis are 7x and 10x. After 6 years the age is,    x = 4
Age difference between Melwyn and Louis
= 10x – 7x
= 3x = 3 × 4
= 12 years [Putting, x = 4]

9. b
Let Purvi’s present age be x years
Therefore Anil’s present age = 1.5x years
After 8 years 27x + 144 = 25x + 200
=>x = 28 years

10. a
Let year ago the ratio of their ages was 3:5. According to the question,       Governmentadda Suggests ixambee Courses RBI Grade B + NABARD Grade A Course Click Here FCI AGM Technical Course Click Here FCI AGM GA Course Click Here  