# Solution to Coded Inequality with explanation

1. 5;

Given statements: R > S > T > U > X … (i)
T < V < W … (ii)
Combining both the statements, we have
W > V > T > U > X
or, W > X or X < W. Hence, conclusion II is true.
Again, from (i), R > X is true.
Hence, conclusion I follows.

2. 1;

Given statements: E = F < G < H … (i)
G > I … (ii)
Combining both the statements, we have
I < G < H, Thus, I < H. So, H > I is true.
Hence, conclusion I follows.
Again, E = F < G > I
We can’t compare E and I.
Hence, conclusion II does not follow.

3. 1;

Given statements: A > B > F > C … (i)
D > E > C … (ii)
From (i), we have,
A > C, so C < A is true.
Hence, conclusion I is true.
Again, combining both the statements, we have
A > B > F > C < E < D
We can’t compare B and D.
Thus, conclusion II does not follow.

4. 3;

Given statements: K < L < M = N … (i)
P > O > N … (ii)
Combining both the statements, we have
K < L < M = N < O < P
Thus, K < P, means K < P may be true. And
K = P may also be true.
Hence, either conclusion I or II follows.

5. 2;

Given statements: D < E < F < G … (i)
K > F … (ii)
Combining both the statements we have,
K > F < G
We can’t compare K and G.
Thus, conclusion I does not follow.
Again, D < E < F < K.
Thus, D < K. So, K > D is true.
Hence, conclusion II follows.

6. 1;

Statements: N > O > P = Q > R
Thus, N > R is true. Hence, I is true, but conclusion II does not follow.

7. 4;

Statements: Given expressions:
W < X < Y = Z > A … (i)
W < B … (ii)
Combining both the expressions, we have
B > W < X < Y = Z > A
We can’t compare B and Z.
Thus, conclusion I is not true. Also we can’t compare W and A. Hence, conclusion II is not true.

8. 5;

Given expressions H > I > J > K … (i)
L < M < K … (ii)
Combining both expressions, we have
H > I > J > K > M > L
Thus, I > M is true. Hence, conclusion I follows.
Again, H > L means L < H, so conclusion II is also true.

9. 4;

Given expression C < D < E … (i)
D > F > G … (ii)
Combining both the expressions,
C < D > F > G
We can’t compare C and G.
Thus, conclusion I is not true.
F < D < E
Hence, F < E. Thus, conclusion II is not true.

10. 2;

Given expression R > S > T > U … (i)
V < T … (ii)
Combining both the expressions,
V < T > U
We can’t compare V and U.
Thus, conclusion I is not true.
Again, R > S > T > V, so, R > V or V < R. Thus, conclusion II is true.