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# Solution to the quiz NABARD Grade A & B Online Course Get Course Now 150+ RRB NTPC Previous Solved Papers PDF Free Download Now RBI Grade B Complete Online Course Register Today RRB JE Free Study Material PDF Books Free Download Now RRB NTPC Free Study Material PDF Free Download Now All Exam Free Study Group (Free Videos,Pdf,Mock etc) Join Right Now

1. Option C
→ No. of illiterate female from village B = 60 % (700) = 420
→ No. of illiterate from village B= (9/20)* 2000 = 900
Therefore,
→ No. of illiterate male from village B= 900- 420 =480
→ No. of male from village B = 65 %( 2000) = 1300
→ % of male, who is illiterate from village B = (480/1300) * 100 = 36.9 ≈ 37 (ans)

2. Option B
→ No. of Literate from village A = (2/5)*750 = 300
→ No. of Literate from village B = (11/20)*2000 = 1100
→ No. of Literate from village C = (13/15)*1500 = 1300
→ No. of Literate from village D = (4/5)*2750 = 2200
→ No. of Literate from village E = (1/4)*2500 = 625
→ No. of Literate from village F = (11/30)*3000 = 1100
→ Total no. of literate in all villages= 300+1100+1300+2200+625+1100 = 6,625
→ Total no. of people in all villages= 750+2000+1500+2750+2500+1100 =12,500
→ % of literate people in all villages = (6,625/12,500)* 100 = 53 % (ans)

3. Option C
→ Illiterate from village B= 2000-1100 =900
→ Illiterate from village C=1500-1300 =200
→ Illiterate from village D= 2750-2200 =550
→ Female from village A= 48% (750) = 360
→ Female from village E= 61% (2500) = 1525
→ Female from village F= 25% (3000) = 750
→ Ratio = (900+200+550) : (360 + 1525+750) = 1650 : 2635 = 330 : 527 (ans)

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4. Option D
→ Since we don’t have enough data for village F
→ We cannot determine the answer

5. Option A
→ Female from village A= 360
→ Female from village C = 825
→ Total = 1185
→ Female from village D= 825
→ Female from village F= 750
→ Total= 1575
→ Less% = [(1575 – 1185) /1575] * 100 = (390/1575)* 100
= 24.76 % (ans)

6. Option C
→ No. of students cleared from Maths department = (60/360) * 847 = 141
→ No. of students appeared from English department = (27/ 100)* 5484 ≈ 1481
→ Difference = 1481-141 = 1340 (ans)

7. Option D
→ No. of students cleared from commerce & other dept. = [(72+67) /360]*847 = (139/360)* 847 = 327
→ No. of students cleared physics department = (42/360)* 847 = 99
→ X= (327/99)* 100
→ X= 330 % (ans)

8. Option C
→ Ratio = (Maths +Physics): (Chemistry + Commerce) = (18+14): (11+23) = 32: 34 = 16:17 (ans)

9. Option A
English Department:
→ Appeared = (27/100) * 5484 = 1481
→ Cleared = (88/360)* 847=207
→ Difference = (1485-207) = 1274
Maths Department:
→ Appeared = (18/100) * 5484 = 987
→ Cleared = (60/360)* 847=141
→ Difference = (987-141) = 846
Physics Department:
→ Appeared = (14/100) * 5484 = 768
→ Cleared = (42/360)* 847=99
→ Difference = (768-99) = 669
Chemistry Department:
→ Appeared = (11/100) * 5484 = 603
→ Cleared = (31/360)* 847= 73
→ Difference = (603-73) = 530 (ans)
Commerce Department:
→ Appeared = (23/100) * 5484 = 1261
→ Cleared = (72/360)* 847= 169
→ Difference = (1261-169) = 1092
Other Departments:
→ Appeared = (7/100) * 5484 = 384
→ Cleared = (67/360)* 847= 158
→ Difference = (384-158) =226

10. Option B
→ No. of students not cleared= (5484 -847) = 4637
→ % of students not cleared = (4637/5484) *100 = 84.55 %
(ans)

11. Ans. D.
Solution:
240000×19% – 144000×15%
=45600-21600
=24000

12. Ans. C.
Solution:
Income of A and B: Expenditure of E and F
240000×(15+20)%:144000×(20+18)%
240000×35%:144000×38%
240×35:144×38
8400:5472
175:114

13. Ans. E.
Solution:
Saving = Income-Expenditure
=240000×(20+18)% – 144000×(17+17)%
=240000×38% – 144000×34%
=91200-48960
=42240

14. Ans. A.
Solution:
240000×(15+12+18)%/3
=240000×45%/3
=36000

15. Ans. C.
Solution:
Now the income of F= 240000×19%×110/100 =50160
The expenditure of F= 144000×20%×105% =30240
Saving= 50160-30240 =19920

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