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**In this article, I have solved questions where some workers quit in the middle, as well as some questions on efficiencies.**

** Note: **In the complete Time and Work series, Efficiency would mean “Work Done in 1 day”, and efficiency has been denoted by small letters, e.g. “a” means “Efficiency of A”.

**1)**

If Pratibha finishes the work in X days, then Sonia will take 3X days to finish the same work

Given 3X – X = 60

Or X = 30

Pratibha takes 30 days and Sonia takes 90 days

**Answer: (A)**

**2)**

Let the total work be 24 units.

Efficiency of Sunil = 24/4 = 6 units (Since Sunil takes 4 days to complete the work)

Efficiency of Ramesh = 6 * 1.5 = 9 units (Since Ramesh is 1.5 times efficient as Sunil)

Efficiency of Dinesh = 24/6 = 4 units ((Since Sunil takes 6 days to complete the work))

Efficiency of (Sunil + Ramesh + Dinesh) = 6 + 9 + 4 = 19 units

Time required to finish the complete work = 24/19 days

**Answer: (D)**

**3)**

Let the total work be 15 units. Efficiency of A = a and Efficiency of B = b

A and B complete the work in 5 days.

Hence efficiency of A and B = 15/5 = 3 units

So, a + b = 3 … (1)

New efficiency of A = 2a

New efficiency of B = b/3

With new efficiency the work was completed in 3 days.

So, 2a + b/3 = 15/3 = 5 … (2)

Solve (1) and (2), you will get a = 12/5 = 2.4 units

So A will complete 15 units work in 15/2.4 or 25/4 days

**Answer: (B)**

**4)**

Let the total work be 24 units

Given, 3*Efficiency of A = Efficiency of B + Efficiency of C

3a = b + c

A, B and C compete the work in 24 days.

Hence, a + b + c = 24/24 = 1 or 4a = 1 [Put b + c = 3a]

a = 1/4 = 0.25 unit

A completes 0.25 unit work in 1 day. So to complete 24 units of work, he will take 24/0.25 = 96 days

**Answer: (B)**

**5)**

Let the total work be 7 units. Since they all complete the work in 7 days, so their total efficiency = 7/7 = 1 unit

Let efficiency of boy = x

Then efficiency of women = 2x

Efficiency of man = 4x

x + 2x + 4x = 1

7x = 1 or x = 1/7

The boy completes 1/7 work in 1 day, so to complete 7 units of work, he will take 49 days

**Answer: (A)**

**6)**

A does 1/2 as much work as B in 3/4 of the time. Hence A will do (1/2 + 1/2) or complete work in (3/4 + 3/4) or 1.5 times more time than B.

A = 1.5B (where A = no. of days taken by A to finish the work and B = no. of days taken by B to finish the work)

Also A*B/(A+B) = 18

Put A = 1.5B in the above equation and solve

B = 30 days

**Answer: (B)**

**7)**

Let the total work = 60 units

Efficiency of A = 60/20 = 3 units

Efficiency of B = 60/30 = 2 units

Efficiency of (A + B) = 5 units

Work done by A and B in 7 days = 5*7 = 35 units

Work left = 60 – 35 = 25 units

C completes 25 units of work in 10 days. Hence he will complete 60 units of work in 10* 60/25 = 24 days

**Answer: (C)**

**8)**

Let total work be 120 units.

Efficiency of A = 120/6 = 20 units

Efficiency of B = 120/12 = 10 units

Efficiency of C = 120/15 = 8 units

Work left = 7/8 * 120 = 105 units

Efficiency of A + B = 30 units

Hence time taken by A and B to complete 105 units of work = 105/30 = 3.5

**Answer: (C)**

**9)**

Let the total work = 80 units

Efficiency of (A + B + C) = 80/40 = 2 units

Work done by (A + B + C) in 16 days = 16 * 2 = 32 units

Remaining work = 80 – 32 = 48 units

B and C complete the remaining work (48 units) in 40 days.

Efficiency of B + C = 48/40 = 1.2 units

Efficiency of A = Efficiency of (A + B + C) – Efficiency of (B + C) = 2 – 1.2 = 0.8 unit

Time taken by A to complete the whole work = 80/0.8 = 100 days

**Answer: (C)**

**10)**

Let the total work = 360 units

Efficiency of A = 360/45 = 8 units

Efficiency of B = 360/40 = 9 units

Efficiency of A + B = 17 units

Let A left after x days, that means A and B worked together for x days. Total work done by A and B together = 17x

Then the remaining work is finished by B in 23 days. Hence work done by B alone = 23 * 9 = 207 units

So, 17x + 207 = 360

Or x = 9 days

**Answer: (D)**

**11)**

This question appeared in SSC Tier-2 2015, and stumped many candidates. Although there is nothing tricky about it.

Let the total work be 60 units.

p + q = 60/6 = 10

q + r = 60*7/60 = 7

Given, Total work done = 3 days work of P + 6 days work of Q and R

60 = 3*p + 6*(7)

p = 6

Hence time taken by P to complete the work = 60/6 = 10 days

p + q = 10, hence q = 4

q + r = 7, hence r = 3

Hence time taken by R to complete the work = 60/3 = 20 days

Difference = 20 – 10 = 10 days

**Answer : (C)**

**Q. 12) 4 Men and 6 Women working together can complete the work in 10 days. 3 men and 7 women working together will complete the same work in 8 days. In how many days 10 women will complete this work?**

**
**One day work for a man = 1/m

One day work for a woman = 1/w

In one day, 4 men and 6 women will do 1/10 of the work. Hence,

4/m + 6/w = 1/10 … (i)

Similarly,

3/m + 7/w = 1/8 … (ii)

Multiply equation (i) with 3 and equation (ii) with 4

12/m + 18/w = 3/10

12/m + 28/w = 1/2

Subtract the equations

10/w = 1/5

So 10 women will complete the work in 5 days

**Answer: (5)**

**If you have any doubt in this article, please drop a comment…**

**Keep reading 🙂**