Formulas & Short Tricks on Algebra

Numerical ability section is considered to be one of the toughest subjects of Competition Exams but it can be the most scoring area if prepared well. Scoring in this section can be easy or tough depending on the complexity of the questions and your understanding of the questions.

From the past 2 years, Advanced Maths has become the most favorite area of SSC CGL Exam which include questions on Algebra, Trigonometry, Mensuration and Geometry. You can expect around 27-30 questions from Advanced Maths in SSC Exams.

It is one of the biggest myth about SSC CGL Exam that you cannot master these Advanced Maths topics. Today we will be covering a very important topic from the Advance Maths part of the Quantitative Aptitude section that is – Basic Formulas & Short Tricks on Algebra.

Important Formulae


 If  then 

Types of Questions Asked in SSC Exams

Type 1.   If , find the value of 

Ans.

Squaring both side

Squaring both sides again,

Type 2: If  find the value offind the value of  

Ans.

Squaring both sides again

Type 3: Find the value ofif 

Ans. 

 = 9 – 8  = 1

Type 4:  If then find the value of

Ans:

Cubing both sides,

 

 

Type 5: If then find the value of 

Ans. 

Squaring both sides,

Putting the value of 

Type 6 If , find the value of

Ans:

(Dividing by x y z)

…. (Formula)

Type 7 If  then the value of 

Ans:formula

We do not know the value of xy + yz + zx. First find it.

formula

Important Questions on Algebra with Short Trick

(1)If 
then the value of 
 

 

(a)4

(b)52

(c)   64

(d)  76

Ans. (b)

Cubing both sides,

 

(2) If  then the value of 

 

(a) 1

(b)2

(c)

(d)

Ans. (b)

   if difference of square of terms  of X is 1 then 1/x is always same but the sign between the terms of X change as happen in this question

(3) If  then the value of   is

(a)2

(b) 4

(c)   8

(d)  16

Ans.(a)

Similarly,

 

(4) If  then the value of

(a)122

(b)118

(c)123

(d)120

Ans. (c)

(5)If then is equal to:

(a)0

(b)1

(c)   2

(d)  3

Ans. (a)

  always remeber if x+ 1/x=√3 then X6+1=0 holds true

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