Solutions
Q1 Option D
Quantity1:
Total weight of 11 persons = 42*11 =462
Total weight of first 5 persons = 36*5 = 180
Total weight of last 5 persons = 41*5 =205
Weight of 6 one = 462- (180+205) = 77kg
Quantity 2:
Average of five consecutive odd numbers = 45(It should be a middle number) <=(If the difference is equal, then the middle no will be your average value)
So, the series must be
41, 43,45,47,49
Sum of first and last number = 49+41= 90 kg
Quantity I < Quantity II
Q2 Option C
Quantity1:
Total cost price = 15000+1000 =16000
Selling price = 20000
Profit = 20000-16000 =4000
Quantity2:
Cost price of an article = sp –profit
= 2500-250 = 2250
Quantity I > Quantity II
Q3 Option C
Quantity1:
50km in half an hour
Speed = 100km/hr
60 -100
225 – ?
Total distance travelled = 375km
Quantity2:
Quantity I > Quantity II
Q4 Option B
Quantity1:
Quantity 2:
Quantity I ≥ Quantity II
Q5 Option C
Quantity1:
Area of circle,
=
r = 110.25
r = 10.5 m
Circumference =
Total cost = 66*27.5 = Rs.1815
Quantity 2:
Investment ratio = 7: 8
Total investment ratio = 7*9: 8*12 = 63: 96 = 21:32
A’s profit =
Quantity I > Quantity II
Q6.Option D
Quantity1:
Speed =207 *(5/18) =57.5m/s
Time = (650/57.5) =11.3 sec
Quantity 2:
Speed of Train A = 250/25 = 10m/sec
Time taken to cross each other = (250+320) / (25+10) = 16.28sec
Quantity I < Quantity II
Q7 Option D
5 years ago, A_B= 8:5 (we assume this as 8x and 5x)
2 years hence, A_B= 5:4
32x+28= 25x+35
7x=7
=>x=1
The present age of Suba= 8x+5 =13 years
Quantity 2:
After 5 years, A_B= 3:4 (we assume this as 3x and 4x)
4 years hence, A_B= 29:39
3x-1/4x-1 = 29/39
117x-39=116x-29
=>x= 10
The present age of A= 3x-5 = 25 years
Quantity I < Quantity II
Q8 Option D
Quantity 1:
Average of first 10 odd number = (1+3+5+7+9+11+13+15+17+19)/10=10
(or)
If the difference is equal, then the average will be the middle number. Here the middle no is 9 and 11. So, the average is (9+11)/2 = 20/2=10
Quantity 2:
Average of first 10 prime number = (2+3+5+7+11+13+17+19+23+29) =129/10 =12.9
Quantity I < Quantity II
Q9 Option C
Quantity 1:
1/7 -1/9 = 9-7 / (9*7) = 2/63 = 1/31.5
Total time taken = 31.5 hrs
Quantity 2:
One tap can fill tank in 6 hours and another tap can fill the tank in15 hours
The total capacity of the tank is 30. (ie., LCM of 6 and 15)
Total hours per hour capacity
Tap 1=> 6 5
Tap 2=> 15 2
Both tap are opened alternatively.
The first two hours the capacity of tap 1 and 2 is 7. So, 7*4= 28(8 hour capacity)
Remaining 2 will be there. Remaining will be filled by tap 1. So, 2/5 hr
The tank will be filled in hrs
Quantity I > Quantity II
Q10 Option D
Quantity1:
Probability = 4C2 /52C2 = 6/(26*51) = 1/221
Quantity 2:
Total Probability = 6 =36
Divisible by 2 = 18 possibilities
Probability = 18/36 = 1/2
Quantity I < Quantity II
