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ANSWERS
1—(c) Ayesha’s and Amita’s 1 day’s work
= 1/16 + 1/8 = (1 + 2)/16 = 3/16
∴ Ayesha and Amita together can complete the work in
= 16/5 = days/
2—(a) 72 men = 144 women = 180 children
= 2 men = 4 women = children
∴ 4 men + 12 women + 20 children
= 4 men + 6 men + 8 men = 18 men
When 6 men do 1 work in 12 days. 18 men will do the same in 4 days
∴ Remaining work = ½ Now, M1D1/W1 = M2D2/W2
= ½ × 6 × 12 = 1 × M2
= M2 = 36 = Number of men
3—(a) [Tricky approach]
= 18 men = 5 × 18 = 90 women
∴ 1 men = 5 women
∴ 4 men + 0 women = 30 women, M1D1 = M2D2
= 5 × 18 = 30 D2
= D2 = (5 × 18)/30 = 3 days
4—(a) 8 × 20 men = 8 × 32 women
=5 men = 8 women
5 men + 8 women = 16 women M1D1 = M2D2
= 8 × 32 = 16 × D2
= D2 = (8 × 32)/ 16 = 16 days
5—(b) 2 × 6 men = 18 women
= 24 children
2 men = 3 women = 4 men part of work done in1 day by 4 men = 1/3
∴ Remaining 2/3 work will be finished by 8 men in1 day. Hence, 8 men would be required.
6—(d) Number of days = 9800/350 = 28
7—(d) Part of the tank filled in 1 hour when all the taps are opened
= ¼ + 1/6 – 1/3
= (3 + 2 + 4)/12 = 1/12
Hence, the tank will be filled in 12 hours.
8—(b) 4 × 8 girls = 3 × 9 boys
= 7 × 2 men =5 × 4 women
= 32 girls = 27 boys = 14 men
= 20 women
9—(b) 2 men =3 women
1 man + 1 woman
= ( 3/2 + 1) women = 5/2 M1D1 = M2D2
= 3 × 4 = 5/2 × D2
= D2 = (3 × 4 × 2)/5 = 24/5 days
10—(c)
= 2 × 20 × x × = 4 × 10 × 5 × 2
= x = (4 × 10 × 5 × 2)/ (2 × 20)
= 10 hours
