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Questions (1-10): You have to solve equation I and II ,Give answer
1)If X>Y
2)If X<Y
3)If X≥ Y
4)If X≤ Y
5)If X=Y or cannot be established
Solutions
- Solution: 1)X>Y
Explanation :
(x-4)(4x-3) = 0
x=4,3/4
(y+2)(3y+2) = 0
y=-2, -2/3
X>Y - Solution: 3)X≥ Y
Explanation :
(4x-1)(5x-3) = 0
x=1/4, 3/5
(4y-1)(5y-1) =0
y= 1/4, 1/5
X≥ Y - Solution: 4)X≤ Y
Explanation :
(x+2)(x+3) = 0
x=-2,-3
(y+1)(y+2) = 0
y=-1,-2
X≤Y - Solution: 5)X=Y or cannot be established
Explanation :
(x-4)(x+18) = 0
x=4,-18
(y+3)(3y+5) = 0
y= -3, -5/3 - Solution: 1)X>Y
Explanation :
(5x+2)(5x+3) = 0
x= -2/5, -3/5
(5y+10)(y+2) = 0
y= -2, -10/5 = -2, -2
X>Y - Solution: 2)X<Y
Explanation :
y = 1705 – 1689 = 16
(x + y)^2 = 900
x + y = 30
x = 30 – 16 = 14
16>14
x < y - Solution: 5)X=Y or cannot be established
Explanation :
9x – 3x = 64.55 + 19.45
6x = 84
x = 14
√(y *155) = 7 + 6 =13
y + 155 = 169
y = 169 – 155 = 14
X=Y - Solution: 4)X≤ Y
Explanation :
2X^2 + 19X + 44= 0
(x + 4) (2x + 11) = 0
x= -4 or -11/2
2Y^2 + 3Y – 20 = 0
(y + 4) (2y – 5) = 0
Y = -4 or 5/2
X≤ Y - Solution: 1)X>Y
Explanation :
(4x+7)(x+3) = 0
x =-7/4, -3
(2y+9)(y+7) = 0
y= -9/2, -7
X>Y - Solution: 3)X≥ Y
Explanation :
(4x+5)(2x+3) =0
x=-5/4, -3/2
(2y+5)(2xy+3) =0
y=-5/2, -3/2
X≥Y
